Q: What number as a remainder of 1 when divided by 2 as a remainder of 2 when divided by 3 as a remainder of 3 when divided by 4 and a remainder of 4 when divided by 5?

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It is an integer which, when divided by 2, leaves a remainder of 1.

3 divided by 2 has a remainder of 1. Which is 1 less than 2.

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solve it with a calculater

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Related questions

It is an integer which, when divided by 2, leaves a remainder of 1.

3 divided by 2 has a remainder of 1. Which is 1 less than 2.

29

solve it with a calculater

57

17

Put the remainder over the number you originally divided by. 15 divided by 7 = 2, remainder 1 = 2 and 1/7

No number can satisfy these conditions: To have a remainder of 1 when divided by 6, the number must be odd (as all multiples of 6 are even and an even number plus 1 is odd) To have a remainder of 2 when divided by 8, the number must be even (as all multiples of 8 are even and an even number plus 2 is even) No number is both odd and even. → No number exists that has a remainder of 1 when divided by 6, and 2 when divided by 8.

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It is not possible, because the number 4 is divisible by 2, and it's remainder is divisible by 2 also, so whatever number works for the "4 with a remainder of 2", will never work for "2 with a remainder of 1.

The LCM of 2, 3, 4 and 5 is 60. Since you need a remainder of 1 just add 1. So the answer is 61. Or any number that is 1 more than a multiple of 60.

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