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What number divided by 2 has a remainder 1 divided by 3 has a remainder 1 divided by four has a remainder 1 divided by 5 has a remainder 1 divided by 6 has a remainder 1 divided by 7 has a remainder 0?
Wiki User
∙ 10y ago
301, which can be shown as follows:
301/2 = 150 R 1
301/3 = 100 R 1
301/4 = 75 R 1
301/5 = 60 R 1
301/6 = 50 R 1
301/7 = 43 R 0
In terms of mathematical congruence classes, we need only find a number evenly divisible by 2, 3, 4, 5, and 6 (the smallest is the LCD, 60), and add 1 to get 61, which has a remainder of 1 upon division by 2, 3, 4, 5, and 6. To get a number such that division by 7 yields a remainder of 0, simply add 60 to 61 enough times to reach a number evenly divisible by 7; the smallest is 301:
61 + 4*(60) = 301
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The other numbers that meet the criteria will be those multiples of 7 that are also one more than a multiple of 60, i.e. higher by the LCD of 2,3,4,5,6, and 7, which is 420.
The next numbers are 721, 1141, 1561, and 1981.
Wiki User
∙ 10y ago
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How do you get 1407 divided by 7 in long division?
201
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0.6154
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201
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What is the smallest number a remainder of 8 when divided by 13?
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