The remainder is 0.
If A has a remainder of 1 when divided by 3, then A = 3m + 1 for some integer m
If B has a remainder of 2 when divided by 3, then B = 3n + 1 for some integer n
→ A + B = (3m + 1) + (3n + 2)
= 3m + 3n + 1 + 2
= 3m + 3n + 3
= 3(m + n + 1)
= 3k where k = m + n + 1 and is an integer
→ A + B = 3k + 0
→ remainder when A + B divided by 3 is 0
-------------------------------------------------------------------------
From this, you may be able to see that:
multiply ur answer and the number u divided it with and add the remainder
You divide when there is a remainder the same as you divide when there is none. The only difference is that when you divide the last digit in the dividend, you will wither add a decimal point and 0 to the right of the digit and keep dividing, designate the leftover number as a remainder, or you will put the remainder over the divisor to show the remainder as a fraction. For example: 761 divided by 10 is 76 with a remainder of 1. You can write 76 R1, 76 1/10 or 76.1
A lot of numbers divided by seven get a remainder of four. Well, eleven, eighteen, twenty-five, and thirty-two are some. This is a very broad question that can be answered many ways. The way to get the remainder of four is to find a multiple of seven and add four then you divide and the remainder is four.
The LCM of 2, 3, 4 and 5 is 60. Since you need a remainder of 1 just add 1. So the answer is 61. Or any number that is 1 more than a multiple of 60.
101.3333
The process of multiplication doesn't produce remainders.The process of division does.If you want to divide a 3-digit number by a one-digit numberand get a remainder of 8, try these:107 divided by 9116 divided by 9125 divided by 9134 divided by 9143 divided by 9..Add as many 9s to 107 as you want to, and then divide the result by 9.The remainder will always be 8.
multiply ur answer and the number u divided it with and add the remainder
You divide when there is a remainder the same as you divide when there is none. The only difference is that when you divide the last digit in the dividend, you will wither add a decimal point and 0 to the right of the digit and keep dividing, designate the leftover number as a remainder, or you will put the remainder over the divisor to show the remainder as a fraction. For example: 761 divided by 10 is 76 with a remainder of 1. You can write 76 R1, 76 1/10 or 76.1
A lot of numbers divided by seven get a remainder of four. Well, eleven, eighteen, twenty-five, and thirty-two are some. This is a very broad question that can be answered many ways. The way to get the remainder of four is to find a multiple of seven and add four then you divide and the remainder is four.
If the digits of the number you're dividing by 3 add up to a multiple of 3, the whole number is divisible by 3 and there will be no remainder. If they don't add up to a multiple of 3, there will be a remainder.
The LCM of 2, 3, 4 and 5 is 60. Since you need a remainder of 1 just add 1. So the answer is 61. Or any number that is 1 more than a multiple of 60.
101.3333
No remainder. It has the same rule as 3 for divisibility. Add them up and if that is divisible by 27 then the number is divisible by 27.
The remainder can only be one, so make it whatever number plus 1/2
506
256
No. Add the digits of the dividend and if that is divisible by 3 then the original number is divisible by 3; if not, its remainder when divided by 3 gives the remainder when the original number is divided by 3: 1 + 2 + 1 = 4 which gives a remainder of 1 when divided by 3, so 121 divided by 3 gives a remainder of 1. (121 = 40 x 3 + 1)