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Q: What number has 2 digits and is divisible exactly by 5 and 7?

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2,4,6,8,and 0 are divisible by 2 in the ones digit. Zero is only divisible in a number with 2 digits or more. 0 itself is not divisible by 2.

I am a 3 digit number divisible by 7 but not 2 the sum of my digits is 4 what number am I

If the number formed by the last three digits is divisible by 8. Alternatively, if the number is divisible by 2, the quotient is divisible by 2 and that quotient is divisible by 2.

No. 26 for instance the sum of the digits is 8 but not divisible by 4. 32 the sum of the digits is 5 but divisible by 4 The rules for some other numbers are 2 all even numbers are divisible by 2 3 The sum of the digits is divisible by 3 4 The last 2 numbers are divisible by 4 5 The number ends in a 0 or 5 6 The sum of the digits is divisible by 3 and is even 7 no easy method 8 The last 3 numbers are divisible by 8 9 The sum of the digits is divisible by 9

A number is divisible by 2 if that number is an even number, which means it ends in 0, 2, 4, 6, or 8. A number is divisible by 3 if the sum of its digits is evenly divisible by 3.

Sum of digits of 627 = 6+2+7 = 15 15 is exactly divisible by 3. Hence, 627 is divisible by 3. So, it is not a prime number

# Exactly divisible by 2. # Characterized or indicated by a number exactly divisible by 2.

If a number is divisible by 2 (an even number) and 3 (the sum of the digits is divisible by 3) then the number is divisible by 6.

There is no number, no matter the number of digits, that is only divisible by 2.

If the last 2 digits are divisible by 4, then the entire number is divisible by 4. The reason this works is related to the fact that 100 is a multiple of 4.If the last 2 digits are divisible by 4, then the entire number is divisible by 4. The reason this works is related to the fact that 100 is a multiple of 4.If the last 2 digits are divisible by 4, then the entire number is divisible by 4. The reason this works is related to the fact that 100 is a multiple of 4.If the last 2 digits are divisible by 4, then the entire number is divisible by 4. The reason this works is related to the fact that 100 is a multiple of 4.

NO, can 2 be divided by 6........ yes, can 4 be divided by 6......... Every number is divisible by every other number, but not always exactly. Not every number that is exactly divisible by 2 is exactly divisble by 4. Examples: 2, 18, 30, 46

You can tell if the last 2 digits of the number can be divisible by 4 or 8. So the number 3156372856374856386578365864would be divisible by 8 because 8 can go into 64.

The digital root (sum of digit) must be divisible by 9, and the number formed by the last 4 digits must be divisible by 16. The second requirement ensures that the number is divisible by 16.

11

1. Sum of digits (12) is divisible by 3, so number is divisible by 3 2. It's an even number so it's divisible by 2 3. If it's divisible by both 3 and 2 then it's divisible by 3 x 2, ie 6.

If a number is divisible by three you will know if all the digits of a number add up to a number divisible by three. Example: 1542 is your number, to find out if it is divisible by three you must add up the digits. 1+5+4+2=12. The number 12 is divisible by three(4x3) so therefore 1542 is divisible by three.

Yes it is - you get the answer 227. To check if a number is divisible by 9, add up the digits that are in it. If the sum of the digits is 9 (or a multiple) then the number itself will also divide exactly by 9. - in this case 2+4+3 = 9.

To know if a number is composite without listing its factors, you can use these rules:All numbers that end with 2, 4, 6, 8, and 0 (even numbers) are divisible by 2.If the sum of the digits in a number is divisible by 3, the number is divisible by 3.If the last two digits are divisible by 4, the number is divisible by 4.All numbers that have 5 in the one's place are divisible by 5.If a number is divisible by 2 AND is divisible by 3, it is divisible by 6.If the last 3 digits of a number are divisible by 8, the number is divisible by 8.If the sum of the digits of number is divisible by 9, the number is divisible by 9.If a number ends wuth 0, the number is divisible by 10.

1- Any number is divisible by 1. 2- Any even number is divisible by 2. 3- If its digits add up to a number divisible by 3, the whole number is divisible by 3. 4- If the last two digits are divisible by 4, the whole number is divisible by 4. 5- If it ends in 5 or 0, the whole number is divisible by 5. 6- If it's even and also divisible by 3, the whole number is divisible by 6. 7- There is no rule for 7. 8- If the last three digits are divisible by 8, the whole number is divisible by 8. 9- If its digits add up to a number divisible by 9, the whole number is divisible by 9. 10- If it ends in 0, the whole number is divisible by 10.

no, it is not. You can check by adding the digits and if divisible by 3 so is the number. In your case 2 + 9 + 3 = 14 which is not divisible by 3

The number 313199 is not divisible by 2, because numbers that are divisible by 2 can only end in digits that are 0, 2, 4, 6, or 8.

An even number is exactly divisible by an even number, 1112 divided by 2 is 556

999 is divisible by 9, but not by six; the next lower number divisible by 9 is 990, which is also divisible by 6, so that's the answer. Some shortcuts for divisibility: 0 is divisible by any number. If the last digit of a number is divisible by 2, the number itself is divisible by 2. If the sum of the digits of a number is divisible by 3, the number itself is divisible by 3. If the last TWO digits of a number are divisible by 4, the number itself is divisible by 4. If the last digit of a number is divisible by 5, the number itself is divisible by 5. If a number is divisible by both 2 and 3, it is divisible by 6. If the last THREE digits of a number are divisible by 8, the number itself is divisible by 8. If the sum of the digits of a number is divisible by 9, the number itself is divisible by 9. 990: 9+9+0=18, which is divisible by 9, so 990 is divisible by 9. 18 is also divisible by 3, so 990 is divisible by 3, and since 990 ends in 0 it's also divisible by 2, meaning that it's divisible by 6 as well.

If the number is even, it's divisible by 2. If the sum of the digits is a multiple of 3, the whole number is divisible by 3. If the last two digits are a multiple of 4, the whole number is divisible by 4. If the last digit is a 0 or a 5, the whole number is divisible by 5. If the number is even and divisible by 3, it's divisible by 6. If the sum of the digits is a multiple of 9, the whole number is divisible by 9. If the number ends in 0, it's divisible by 10.