6, 12, 18 and so on.
1, 2 and 3
A number that ends in 3 is an odd number, as it is not divisible by 2. For a number to be a multiple of 6, it must be divisible by both 2 and 3. Since a number ending in 3 is not divisible by 2, it cannot be a multiple of 6. In other words, any number ending in 3 will always have a remainder when divided by 6.
No. To be a multiple of 6, it must pass both the tests for being a multiple of 2 and 3. To be a multiple of 2, the number must be even; 9283 is odd, so is not a multiple of 2 and so it not a multiple of 6.
It asks for the next multiple which is times two from that number like 6 times 2 which equals 12
A number that is divisible by 6 but not by 3 must be a multiple of 6 that is not a multiple of 3. Since 6 is a multiple of 3 (6 = 2 * 3), any multiple of 6 will also be a multiple of 3. Therefore, there is no number that is divisible by 6 but not by 3.
For a number to be a multiple of 6, it must be a multiple of each of its factors, that is, 2 and 3.420 / 3 = 140420 / 2 = 210Yes, 420 is a multiple of 6. 420 / 6 = 70 â–
Any multiple of 6
Any multiple of 6.
6 and 12 are the first two
6
54
54