As 9 is a multiple of 3, any multiple of 9 will do : 9,18,27,36,45,....
120 is one of 75 such numbers.
3 and 1 will go into both number evenly leaving no remainders.
yes
Every multiple of 6 (and the negative of it) is evenly divisible by both 2 and 3.
1 and 3 will go into both numbers evenly
3 goes into 36 and 63 evenly.
All multiples of 6 Numbers are evenly divisible by 6 if they are evenly divisible by both 2 AND 3. Even numbers are always evenly divisible by 2. Numbers are evenly divisible by 3 if the sum of all the individual digits is evenly divisible by 3. For example, the sum of the digits for the number 3627 is 18, which is evenly divisible by 3 but 3627 is an odd number so the number 3627 is not evenly divisible by 6
Seven and three are both prime numbers, therefore their only factors are one and itself. Nine's factors are 9,1, and 3. 3 Goes into 3 evenly, but doesnt go into 7 evenly. Therefore the only number that fits into 9, 7, and 3 evenly is 1. Hope this helps!
Every number is divisible by any non-zero number. Furthermore, 4770 is evenly divisible by both 3 and 9.
3, Its the largest number that goes into both 6 and 39 evenly.
Because 33 is the smallest number that both 3 and 11 divide into evenly with no remainder.
Because 3 is the largest number that divides into both 12 and 15 evenly with no remainder.