45
15
41-- Less than 100-- 42 is the multiple of 7-- 4 + 1 = 5
The answer is a number that is a multiple of 12 and 9 and is between 100 and 199. The multiples of 12 and 9 in this range are 108, 144 & 180. 180 has both the hundreds and unit digits less than 8 (the tens digit).
If the last 2 digits are divisible by 4, then the entire number is divisible by 4. The reason this works is related to the fact that 100 is a multiple of 4.If the last 2 digits are divisible by 4, then the entire number is divisible by 4. The reason this works is related to the fact that 100 is a multiple of 4.If the last 2 digits are divisible by 4, then the entire number is divisible by 4. The reason this works is related to the fact that 100 is a multiple of 4.If the last 2 digits are divisible by 4, then the entire number is divisible by 4. The reason this works is related to the fact that 100 is a multiple of 4.
The three digit number satisfying the requirements is 112. The three digit number must be greater than or equal to 100 and less than 140. To have 7 as a factor it must be a multiple of 7 To be even, it must be an even multiple of 7. The first even multiple of 7 greater than or equal to 100 is: 100 ÷ 7 = 14 r 2 → first even multiple is 16 × 7 = 112 The last even multiples of 7 less than 140 is: 140 ÷ 7 = 20 → last even multiple is 18 × 7 = 126 The sum of its digits must be less than 9: 112 → 1 + 1 + 2 = 4 126 → 1 + 2 + 6 = 9 → only 112 fits all the criteria.
That the number is divisible by 4* and the sum of its digits is a multiple of 3. *If the number has three of more digits then it is only necessary to look at the tens and units to determine if it is divisible by 4, as 4 is a factor of 100 and therefore of any multiple of 100. Examples : 75 : is not divisible by 4 although its digits total 12 which is a multiple of 3. 132 : is divisible by 4 as 32 is divisible by 4, and its digits total 6 which is divisible by 3, then 132 is divisible by 12.
41-- Less than 100-- 42 is the multiple of 7-- 4 + 1 = 5
4 and 16 both qualify.
300, 600 and 900.
I am a number less then 100 two of my factors are 3 and 5 my digits are 1 apart
The answer is a number that is a multiple of 12 and 9 and is between 100 and 199. The multiples of 12 and 9 in this range are 108, 144 & 180. 180 has both the hundreds and unit digits less than 8 (the tens digit).
77
Yes If a numbers last two digits (assuming that it has at least two) is a multiple of 4, the whole number is also a multiple of 4. If the last two digits are 00 (assuming in this case it has at least three digits), the number is also a multiple of 4. For example, 100 and 200 are multiples of 4.
If the last 2 digits are divisible by 4, then the entire number is divisible by 4. The reason this works is related to the fact that 100 is a multiple of 4.If the last 2 digits are divisible by 4, then the entire number is divisible by 4. The reason this works is related to the fact that 100 is a multiple of 4.If the last 2 digits are divisible by 4, then the entire number is divisible by 4. The reason this works is related to the fact that 100 is a multiple of 4.If the last 2 digits are divisible by 4, then the entire number is divisible by 4. The reason this works is related to the fact that 100 is a multiple of 4.
The three digit number satisfying the requirements is 112. The three digit number must be greater than or equal to 100 and less than 140. To have 7 as a factor it must be a multiple of 7 To be even, it must be an even multiple of 7. The first even multiple of 7 greater than or equal to 100 is: 100 ÷ 7 = 14 r 2 → first even multiple is 16 × 7 = 112 The last even multiples of 7 less than 140 is: 140 ÷ 7 = 20 → last even multiple is 18 × 7 = 126 The sum of its digits must be less than 9: 112 → 1 + 1 + 2 = 4 126 → 1 + 2 + 6 = 9 → only 112 fits all the criteria.
No. .0123445553432 is far less than 100.
A number that is at least 10 quintillion but less than 100 quintillion.
64