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Q: What number is less then 100 a multiple of 3 a multiple of 5 the sum of the digits are odd and an odd number?

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41-- Less than 100-- 42 is the multiple of 7-- 4 + 1 = 5

The answer is a number that is a multiple of 12 and 9 and is between 100 and 199. The multiples of 12 and 9 in this range are 108, 144 & 180. 180 has both the hundreds and unit digits less than 8 (the tens digit).

If the last 2 digits are divisible by 4, then the entire number is divisible by 4. The reason this works is related to the fact that 100 is a multiple of 4.If the last 2 digits are divisible by 4, then the entire number is divisible by 4. The reason this works is related to the fact that 100 is a multiple of 4.If the last 2 digits are divisible by 4, then the entire number is divisible by 4. The reason this works is related to the fact that 100 is a multiple of 4.If the last 2 digits are divisible by 4, then the entire number is divisible by 4. The reason this works is related to the fact that 100 is a multiple of 4.

The three digit number satisfying the requirements is 112. The three digit number must be greater than or equal to 100 and less than 140. To have 7 as a factor it must be a multiple of 7 To be even, it must be an even multiple of 7. The first even multiple of 7 greater than or equal to 100 is: 100 ÷ 7 = 14 r 2 → first even multiple is 16 × 7 = 112 The last even multiples of 7 less than 140 is: 140 ÷ 7 = 20 → last even multiple is 18 × 7 = 126 The sum of its digits must be less than 9: 112 → 1 + 1 + 2 = 4 126 → 1 + 2 + 6 = 9 → only 112 fits all the criteria.

That the number is divisible by 4* and the sum of its digits is a multiple of 3. *If the number has three of more digits then it is only necessary to look at the tens and units to determine if it is divisible by 4, as 4 is a factor of 100 and therefore of any multiple of 100. Examples : 75 : is not divisible by 4 although its digits total 12 which is a multiple of 3. 132 : is divisible by 4 as 32 is divisible by 4, and its digits total 6 which is divisible by 3, then 132 is divisible by 12.

Related questions

41-- Less than 100-- 42 is the multiple of 7-- 4 + 1 = 5

4 and 16 both qualify.

300, 600 and 900.

I am a number less then 100 two of my factors are 3 and 5 my digits are 1 apart

The answer is a number that is a multiple of 12 and 9 and is between 100 and 199. The multiples of 12 and 9 in this range are 108, 144 & 180. 180 has both the hundreds and unit digits less than 8 (the tens digit).

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Yes If a numbers last two digits (assuming that it has at least two) is a multiple of 4, the whole number is also a multiple of 4. If the last two digits are 00 (assuming in this case it has at least three digits), the number is also a multiple of 4. For example, 100 and 200 are multiples of 4.

If the last 2 digits are divisible by 4, then the entire number is divisible by 4. The reason this works is related to the fact that 100 is a multiple of 4.If the last 2 digits are divisible by 4, then the entire number is divisible by 4. The reason this works is related to the fact that 100 is a multiple of 4.If the last 2 digits are divisible by 4, then the entire number is divisible by 4. The reason this works is related to the fact that 100 is a multiple of 4.If the last 2 digits are divisible by 4, then the entire number is divisible by 4. The reason this works is related to the fact that 100 is a multiple of 4.

No. .0123445553432 is far less than 100.

A number that is at least 10 quintillion but less than 100 quintillion.

The three digit number satisfying the requirements is 112. The three digit number must be greater than or equal to 100 and less than 140. To have 7 as a factor it must be a multiple of 7 To be even, it must be an even multiple of 7. The first even multiple of 7 greater than or equal to 100 is: 100 ÷ 7 = 14 r 2 → first even multiple is 16 × 7 = 112 The last even multiples of 7 less than 140 is: 140 ÷ 7 = 20 → last even multiple is 18 × 7 = 126 The sum of its digits must be less than 9: 112 → 1 + 1 + 2 = 4 126 → 1 + 2 + 6 = 9 → only 112 fits all the criteria.

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