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That the number is divisible by 4* and the sum of its digits is a multiple of 3.
*If the number has three of more digits then it is only necessary to look at the tens and units to determine if it is divisible by 4, as 4 is a factor of 100 and therefore of any multiple of 100.
Examples : 75 : is not divisible by 4 although its digits total 12 which is a multiple of 3.
132 : is divisible by 4 as 32 is divisible by 4, and its digits total 6 which is divisible by 3, then 132 is divisible by 12.
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Write a rule to determine when a number is divisible by 12?
A number is divisible by 12 if it is divisible by 3 AND it is divisible by 4. Rule 1a (Divisibility by 3): Add up all the digits of the number. Is this number divisible by 3? Rule 1b (Divisibility by 4): Is the number formed by the last two digits of the original number (the number left after deleting the hundreds, thousands, millions etc) divisible by 4? If the answer to 1a is NO, then the number is not divisible by 3 and so not divisible by 12. In this case, obviously, rule 1b is irrelevant. If the answer to 1b is NO, then the number is not divisible by 4 and so not divisible by 12. If the answer to both 1a and 1b is YES, then the number is divisible by 12.
Example of divisibility rule for 21?
a number is divisible by 12 if the number is also divisible by both 3 and 7. You mean a number is divisible by 21 if it is divisible by 3 and 7.
Can a number be divisible by 6 and 12?
Absolutely - any number that is divisible by 12 - is also divisible by 6 !
Determine if a number is divisible by 3?
Check the sum of the digits, if the sum divisible by 3 then the number is divisible by 3. Example 910: the sum of digits= 9 + 1 + 0 = 10, but 10 is not divisible by 3, so the number 910 is not divisible by 3. Example 2154: the sum of digits = 2 + 1 + 5 + 4 = 12, this sum is divisible by 3, so the number 2154 is divisible by 3. if the sum is long you can check the sum of the sum and apply the same rule. Example 52498731: the sum of digits = 5 + 2 + 4 + 9 + 8 + 7 + 3 + 1 = 39, the sum of the digits for 39 = 3 + 9 = 12, so the original number, i.e. 52498731 is divisible by 3.
What is the divisibility for 12?
The number in question is divisible by 3 and 4.A number is divisible by 3 if the sum of the digits is divisible by 3.A number is divisible by 4 if the last two digits is divisible by 4.963,411,024divisible by 3 because 48 is divisible by 3 and24 is divisible by 4, therefore 12 is a GO!If the number is divisible by both 3 and 4.then the number is then divisble by 12.The divisibility rule for three is to add up all the numbers in the number- if the number is a multiple of three, then the number you started with is divisible by three. Example- 91 you do 9+1=10, so that (91) is not a multiple of three. Extra example- 21 2+1=3 and three is a multiple of three.The divisibility rule for four is one I made myself- That is if the number is even slip it in half or divide by two, once you have done that check if the number is even- If it is, that number is a multiple of four, if not that number is not. Example- 30 30÷2=15 which is not even, so that means that 30 is not a multiple of four. Extra example- 148 148÷2=74 which is even, so 148 is a multiple of four.If the number is divisible by 3 and four, then it is divisible by 12.Divisible by 3-If all of the digits in the number add up to a multiple of three, then that original number is divisible by threeDivisible by 4-If the last two digits in a number are divisible by four, then that original number is divisible by 4.Example: 36Divisible by 3?3+6= 99/3=3, so it is divisible by three.Divisible by 4?Of course, we know that 36 is divisible by 4 (36/9=4)So 36 is divisible by 4Therefore, we know 36 is divisible by 12
