3*39 = 117 9*13 = 117
9y - 9 = -117 9y - 9 + 9 = -117 + 9 9y = -108 9y/9 = -108/9 y= -12
117 divided by 9 = 13
No, it is not a prime number. 117 can be divided evenly. 117 divided by 9 is 13.
117 is a composite number and not a prime number because it is divisible by 1, 3, 9, 13, 39, 117
3*39 = 117 9*13 = 117
9y - 9 = -117 9y - 9 + 9 = -117 + 9 9y = -108 9y/9 = -108/9 y= -12
Finding the square root. Remember, though that there are two square roots for every positive number the square roots of 9 are 3 and -3 because 3 * 3 = 9 and -3 * -3 = +9
117 divided by 9 = 13
1 x 117, 3 x 39, 9 x 13 = 117
No, it is not a prime number. 117 can be divided evenly. 117 divided by 9 is 13.
117 is a composite number having the factors 1, 3, 9, 13, 39, and 117.
If limited to integer solutions, the answers are: 1*117, 3*39 and 9*13
An infinite number of of multiples of 117 can be divided by 117.
Multiply by ten and then subtract the number being mutiplied - 22 x 9 = 220 - 22 = 198
117 is a composite number and not a prime number because it is divisible by 1, 3, 9, 13, 39, 117
Well, if you mean 'what does 13 times 9 equal?' then the answer is 117.