3*39 = 117 9*13 = 117
9y - 9 = -117 9y - 9 + 9 = -117 + 9 9y = -108 9y/9 = -108/9 y= -12
117 divided by 9 = 13
No, it is not a prime number. 117 can be divided evenly. 117 divided by 9 is 13.
117 is a composite number and not a prime number because it is divisible by 1, 3, 9, 13, 39, 117
3*39 = 117 9*13 = 117
9y - 9 = -117 9y - 9 + 9 = -117 + 9 9y = -108 9y/9 = -108/9 y= -12
Finding the square root. Remember, though that there are two square roots for every positive number the square roots of 9 are 3 and -3 because 3 * 3 = 9 and -3 * -3 = +9
117 divided by 9 = 13
1 x 117, 3 x 39, 9 x 13 = 117
No, it is not a prime number. 117 can be divided evenly. 117 divided by 9 is 13.
117 is a composite number having the factors 1, 3, 9, 13, 39, and 117.
An infinite number of of multiples of 117 can be divided by 117.
If limited to integer solutions, the answers are: 1*117, 3*39 and 9*13
Multiply by ten and then subtract the number being mutiplied - 22 x 9 = 220 - 22 = 198
117 is a composite number and not a prime number because it is divisible by 1, 3, 9, 13, 39, 117
Well, if you mean 'what does 13 times 9 equal?' then the answer is 117.