13 x 9 = 117
3*39 = 117 9*13 = 117
To find the number, you can set up the equation: -9x = -117. To solve for x, divide both sides by -9, which gives x = -117 / -9. This simplifies to x = 13. Therefore, the number is 13.
9y - 9 = -117 9y - 9 + 9 = -117 + 9 9y = -108 9y/9 = -108/9 y= -12
To determine how many times 9 goes into 117, you can divide 117 by 9. Doing the calculation, 117 ÷ 9 equals 13. Therefore, 9 goes into 117 a total of 13 times.
117 divided by 9 = 13
3*39 = 117 9*13 = 117
9y - 9 = -117 9y - 9 + 9 = -117 + 9 9y = -108 9y/9 = -108/9 y= -12
Finding the square root. Remember, though that there are two square roots for every positive number the square roots of 9 are 3 and -3 because 3 * 3 = 9 and -3 * -3 = +9
To determine how many times 9 goes into 117, you can divide 117 by 9. Doing the calculation, 117 ÷ 9 equals 13. Therefore, 9 goes into 117 a total of 13 times.
117 divided by 9 = 13
1 x 117, 3 x 39, 9 x 13 = 117
No, it is not a prime number. 117 can be divided evenly. 117 divided by 9 is 13.
117 is a composite number having the factors 1, 3, 9, 13, 39, and 117.
An infinite number of of multiples of 117 can be divided by 117.
If limited to integer solutions, the answers are: 1*117, 3*39 and 9*13
Multiply by ten and then subtract the number being mutiplied - 22 x 9 = 220 - 22 = 198
117 is a composite number and not a prime number because it is divisible by 1, 3, 9, 13, 39, 117