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What numbers are dividable by 2 and 5?

Updated: 8/21/2019
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9y ago

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They are the numbers that end with a 0

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Q: What numbers are dividable by 2 and 5?
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Related questions

If one three-digit number is chosen at random from all those that can be made from the above set of digits find the probability that one is not multiple of 5?

An interesting question. The answer is 80%. A number must end in 0 or 5 to be dividable by 5. From 100 to 109 (10 numbers in total), there will be 2 numbers that are dividable by 5. If I then consider the entire set from 100 to 999 is 900 numbers, you have 90 sets of 10 numbers, each set with 2 dividable number, or 180/900 = 2/10 =20%. If 20% are dividable, 80% aren't. Suppose I extended the question, and say my set is all whole positive numbers and zero with n digits or less, where I pick n randomly from 1 to a million. If from this set, a number is picked randomly, what is the chance that it is dividable by 5. Answer: 20%.


Is there any prime numbers divisible by two and why?

2 is the only prime number dividable by 2. to be a prime number, it must only be dividable by 1 and itself. This is the reason why 2 is the only prime number dividable by 2. If any other number was dividable by two then it would not be prime any more


How many numbers less than 215 are dividable by 12 and 18?

5 of them.


Why are al numbers that are divisible by 10 also dividable by 2?

Because 10, itself, is divisible by 2.


Draw a flowchart to accept two numbers and check if the first is divisible by the second?

Convert this in flow chart and see if it can help Start Display "Enter 2 numbers" Accept 2 numbers A & B Divide the A with B Is result Zero? ---- No - A is not Dividable with second Yes - A is Dividable with second End


What are all the numbers dividable by 3?

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Is 154 dividable by 5?

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Up to 36 what numbers are dividable by 4?

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What is the smallest 4-digit number that is dividable by 2 3 5 and 9?

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What is the smallest composite number exactly divisible by 2 3 5 7 11?

Smallest composite number dividable by prime numbers is product of them all. In this case it is: 2x3x5x7x11 = 2310.


What numbers are dividable by 80?

Numbers that are divisible by 80 are itself and any of its other multiples