An infinite number of of multiples of 18 can be divided by 18.
All multiples of 18, which is an infinite number.
Each of these numbers will go evenly into 18: 1, 2, 3, 6, 9, 18.
Any of its multiples
18 divided by 3=6
Yes. 18 can be divided by these numbers without a remainder: 1 2 3 6 9 and 18.
1, 2, 3, 6, 9, 18
No, neither 12 nor 18 are prime numbers. A prime number is a number greater than 1 that can only be divided by 1 and itself. Both 12 and 18 can be divided by numbers other than 1 and themselves, so they are not prime.
9 and 18. 9+18=27. 18 divided by 2=9.
Yes. 6 is a divisor of 18, along with the numbers 1, 2, 3, 9 and 18. Each of these numbers can be divided evenly into 18.
The HCF of both numbers is 1
18 is an even number. In mathematics, even numbers are integers that are divisible by 2 without leaving a remainder. In the case of 18, it can be divided by 2 evenly, as 18 divided by 2 equals 9 with no remainder. Therefore, 18 is classified as an even number.
The number 18 can be evenly divided by the numbers 1, 2, 3, 6, 9, and 18 itself.