1, 2, 3, 6, 9, 13, 18, 26, 27, 39, 54, 78, 81, 117, 162, 234, 351, 702, 1053, 2106
anythng that is a multipleof 2106 ...2105, 4212, 6318 etc
81 and 78 go into 2106.
You need at least two numbers to find either of those.
648
Here's your problem: 3004 - 2106 = 898.
LCM(81, 26) = 2106.
351, 702, 1053, 1404, 1755, 2106 +351 . . .
2
2106
To determine if 2106 is divisible by 6, we need to check if 2106 is a multiple of 6. To do this, we can use the divisibility rule for 6, which states that a number is divisible by 6 if it is divisible by both 2 and 3. First, we check if 2106 is even (divisible by 2), which it is because the last digit is even. Next, we calculate the sum of the digits of 2106 (2+1+0+6=9) and check if this sum is divisible by 3. Since 9 is divisible by 3, we can conclude that 2106 is divisible by 6.
It is
2106/1000