To determine how many times 79 can go into 395, you would divide 395 by 79. The result is 5, as 79 x 5 = 395. Therefore, 79 can go into 395 exactly 5 times without any remainder.
There is nu number before another because the set of numbers is infinitely dense. If you claim that x1 is the number before 395, then what about x2 = (x1 + 395)/2? Then x1 < x2 < 395 that is, x2 is before 395 and nearer to it. And then what about x3 = (x2 + 395)/2 and then x4 etc defined similarly?
5 goes into 395 exactly 79 times
just 90
-20
A single number can't be 'converted' to a 'lower term'. "395" is just that ... 395, and nothing else.A ratio of two numbers, written as a fraction, can often be reduced to lower terms.
All the numbers are odd numbers.
395*395 = 156025
3.5% of 395= 3.5% * 395= 0.035 * 395= 13.825
20 percent of 395 = 7920% of 395= 20% * 395= 20%/100% * 395= 790/10 or 79
79 times
No. It is divisible by these numbers: 1, 2, 5, 10, 79, 158, 395, 790.