Q: What numbers have a product of 56 and a difference of 10?

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4 and 14

(+7 and +8) and (-7 and-8)

56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers

no

7*8=56

The numbers are 56 and 57.

There is no set of odd numbers whose product is 56 since the latter is even.

No becaues as a product of its prime factors: 2*2*2*7 = 56 or as 23*7 = 56

No because as a product of its prime factors: 2*2*2*7 = 56

11, 12 -11, -12

86

-56 and -1 -56+(-1)=-57 -56*(-1)=56

The two numbers with the sum of 15 and the product of 56 are: 7 + 8 = 15 7 x 8 = 56

As a product of its prime factors: 2*2*2*7 = 56

27 29

56

7 and 8

They are: 7 and 8

The numbers are 56 and 57.

4,6,8,10

the product is nothing more then the result from multiplying two or more numbers together. so 56 x 32 =1792

It is: (77+32)*(56-45) = 1199

The product of any mathematical sum is the numbers multiplied together. For example, the product of 7 and 8 is 56. Products can just as validly be used for negative and/or decimal numbers.

63 and 7

The least common multiple of the numbers 56 and 10 is 280.

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