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let this integer be (xy)

(xy) = 10x + y

10x+y = 2.x.y

10x + y - 2xy = 0

2x.(5-y) +y= 0

x= y / 2(y-5)

when the integer provides this condition, it is equal to twice the product of its digits.

And there is such only one integer.

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Q: What numbers make a product of its digits are 6?
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