189
47
7x9=63
7, 3, and -3.
189
1 and 189 3 and 63 7 and 27 9 and 21
There are infinitely many numbers divisible by 63, just multiply 63 by any whole number and you'll get one.
To answer this question, you first need to break the number down into its prime factors: 63 = 3x3x7 To find two numbers that multiply to make 63, one number must be the product of some of these primes, and the other must be the product of the rest (you can also use 1). Thus the possible pairs are: 1x63 3x21 7x9
47
3 x 63 = 189 3 + 63 = 66
1 x 63, 3 x 21, 7 x 9
1 x 63, 3 x 21, 7 x 9