a+b=-7
rearrange:
b= -a-7=-(a+7)
substitute into:
ab=30
-a(a+7)=30
-a^2-7a-30=0
a^2+7a+30=0
x = complex number, therefore there are no two Real numbers that exist that satisfy these two conditions.
-23
-37
-17
-23
-7 and +1
-13
15
-1
161
The numbers are 3 and 4
12
They are: -1 and 8