answersLogoWhite

0

a+b=-7

rearrange:

b= -a-7=-(a+7)

substitute into:

ab=30

-a(a+7)=30

-a^2-7a-30=0

a^2+7a+30=0

x = complex number, therefore there are no two Real numbers that exist that satisfy these two conditions.

User Avatar

Shanie Mills

Lvl 9
3y ago

What else can I help you with?