What numbers multiply to get 30 but add to get 7?

Anonymous

∙ 9y ago

Updated: 5/28/2022

a+b=-7

rearrange:

b= -a-7=-(a+7)

substitute into:

ab=30

-a(a+7)=30

-a^2-7a-30=0

a^2+7a+30=0

x = complex number, therefore there are no two Real numbers that exist that satisfy these two conditions.

Shanie Mills ∙

Lvl 9

∙ 2y ago

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