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Best Answer

a+b=-7

rearrange:

b= -a-7=-(a+7)

substitute into:

ab=30

-a(a+7)=30

-a^2-7a-30=0

a^2+7a+30=0

x = complex number, therefore there are no two Real numbers that exist that satisfy these two conditions.

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Shanie Mills

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βˆ™ 2022-05-28 04:46:17
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Q: What numbers multiply to get 30 but add to get 7?
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