a+b=-7
rearrange:
b= -a-7=-(a+7)
substitute into:
ab=30
-a(a+7)=30
-a^2-7a-30=0
a^2+7a+30=0
x = complex number, therefore there are no two Real numbers that exist that satisfy these two conditions.
-23
-17
-37
The two numbers that multiply to get 35 and add to 2 are 7 and -5. When you multiply them (7 * -5), you get -35, and when you add them (7 + -5), you get 2. Thus, the numbers are 7 and -5.
-23
The two numbers that multiply to -140 and add up to -8 are 7 and -20. When you multiply them, 7 × -20 equals -140, and when you add them, 7 + (-20) equals -8.
The two numbers that add up to -5 and multiply to -14 are -7 and 2. When you add them together, -7 + 2 equals -5, and when you multiply them, -7 * 2 equals -14.
-7 and +1
15
-13
The two numbers that add up to -6 and multiply to -7 are -1 and 7. This is because -1 + 7 = -6 and -1 * 7 = -7. These numbers satisfy both conditions given in the question.
-1