Well, a BB is .177 and a 22 is .22. Close enough?
apparent diameter
Perhaps a flashlight.
area of object = (1/3) pi * radius^2 = (1/3) (pi) * (0.6)^2 = 0.377 Find the diameter of this object (assuming it's a circle), and that's the answer: diameter = radius * 2 radius = square root (area / pi) diameter = 2 * square root (area / pi) diameter = 2 * (0.335) = 0.67
The diameter of an object is twice the radius. Therefore 1,737.4 * 2 = 3,474.8
nominal diameter is the original diameter of an object
Three and three-tenths.
three and five tenths.
http://wiki.answers.com/Q/What_does_a_2_mm_diameter_object_look_like"
The diameter is the height: the tip to the toe of an object.
2 x pi x radius
It is the tenths place.
.2 = 2/10 = 2 tenths