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Q: What ordered pair is on the graph of the equation 3x 7y 11?
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Which ordered pair is a solution of y equals -3x plus 11?

There are an infinite number of ordered pairs that satisfy the equation.


Is there an 11 letter word for ordered pair?

yes ORDERED PAIR


What is the ordered pair of this equation x-y equals 1 5x-4y equals -3?

x - y = 1 so x = y+1 15(y+1) - 4y = -3 15y + 15 - 4y = -3 11y = 12 y = 12/11 x = 12/11 + 1 = 23/11 Ordered pair, then, is (23/11, 12/11)


How the equation and graph have connection?

An equation and a graph are connected because with any equation if y is 11 and x is 12 then you go on the graph on the x axis over 12 and up 11. So if you plug in the x and then whatever y is that is the cororderents on your graph.For example the equation is y=5x+1 then you plug in 5 to x so now the equation is now y=5(5)+1 and y will equal 26 so your cororderents are (5,26)


What is the ordered pair for y equals 2x plus 1 and y equals x -5?

x = -6 y = -11


3 plus 6x equals 11-4y?

You'll need another equation to solve this one. The equation you give has a graph that is a line. Every point on the line is a solution to the equation so there are infinitely many solutions.


What is y equals 3x - 14?

-11


When you shift the graph of an equation up or down does every instance of x in the equation change?

Yes, for example if you have y=x but you shifted the equation up 3 units hence: y=x+3. than you will receive a different y from every instance (point) of x. Reference: collegemathhelper.com/2015/11/horizontal-graph-transformations-for.html


6x - 6y plus 11 equals 17 9y equals 3x plus 15 Solve the system of equations and enter the solution as an ordered pair?

(0,7)


Use the quadratic formula to solve for the ordered pair here is the equation xsquared-7x-18 equals 0?

-b +/- sqrt(b^2 - 4ac)/2a a = 1 b = -7 c = -18 7 +/- sqrt( 49 + 72 )/2 7 +/- 11/2 roots are; 9 and -2 ( my TI-84 confirms this answer )


What is a equation with 11?

y = x - 11 is one possible equation.


Which pair of number does square root 105 fall between?

There is no unique pair of numbers that satisfies these requirements. Suppose a and b is such a pair, and sqrt(105) = x then you want a < x < b But a < (a+x)/2 < x < (b+x)/2 < b So that (a+x)/2 and (b+x)/2 are a closer pair. and you can then find a closer pair still - ad infinitum. The question can be answered (sort of) if it asked about "integers" rather than "numbers". 100 < 105 < 121 Taking square roots, this equation implies that 10 < sqrt(105) < 11 so the answer could be 10 and 11. But (and this is the reason for the "sort of") the above equation also implies that -11 < sqrt(105) < -10 giving -11 and -10 as a pair of consecutive integers. So, an unambiguous answer is possible only if the question specifies positive integers.