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import math

x=1000

c=0

f=[]

for i in range(0,x+1):

if math.sqrt(i)%1==0:

  f.append(i)

for i in range(0,len(f)):

if f[i]%10==6:

c+=1

print((c/len(f))*100)

output:18.75

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unknown1323

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Q: What percent of the perfect squares less than 1000 that end in a 6?
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