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Shirin’s father is four times as old as she is. In 18 years he will be exactly twice as old as her. Find their present ages. please sol

Home/Math/Shirin’s father is four times as old as she is. In 18 years he will be exactly twice as old as her. Find their present ages. please sol

Shirin’s father is four times as old as she is. In 18 years he will be exactly twice as old as her. Find their present ages. please sol

Question

Shirin’s father is four times as old as she is. In 18 years he will be exactly twice as old as her. Find their present ages. please solve my question with full explanation please

## Answers ( )

Answer:let shirins present age be x

then shirins fathers present age is 4x (given)

after 18 years

fathers age will be 4x+18

also shirins age after 18 years is x+18

then given that after 18 years age of father is twice shirins age at that time so

4x+18=2(x+18)

so

4x + 18= 2x + 36

4x-2x=36-18

2x=12

so x=18/2

x=9

so shirins present age is 9 and her fathers present age is 4x i.e 4*9 i.e 36 years

hope it helps…..

Step-by-step explanation:r u from pakistan??

agar aap pakistan se ho toh mera reply please denaa

mera ek question hai