Q: What plane is point p on?

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Let the point P have coordinates (p, q, r) and let the equation of the plane be ax + by +cz + d = 0Then the distance from the point to the plane is abs(ap + bq + cr) / sqrt(a^2 + b^2 + c^2).

Yes, since a plane is a two dimensional surface that extends to infinity in both directions

ab is a straight line in the plane p.

Then it is in the plane!

A reflection in a line l is a correspondence that pairs each point in the plane and not on the linewith point P' such that l is the perpendicular bisector of segment PP'. IF P is on l then P is paired with itself ... Under a reflection the image is laterally inverted. Thus reflection does NOT preserve orientation...

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Definitely not. A plane in only two dimensional and if the point P does not necessarily have to be in those two dimenions. It can be but does not have to be.

It is possible.

1

Let the point P have coordinates (p, q, r) and let the equation of the plane be ax + by +cz + d = 0Then the distance from the point to the plane is abs(ap + bq + cr) / sqrt(a^2 + b^2 + c^2).

apex it’s true on god

It's x = 0. Consider a point of the plane, P=(x, y), in cartesian coordinates. If P is a point belonging to x-axis, then P=(x, y=0); if P is a point belonging to y-axis, then P=(x=0, y).

Yes, since a plane is a two dimensional surface that extends to infinity in both directions

A Cartesian plane is a 2-dimensional, flat surface. The plane has two mutually axes that meet, at right angles, at a point which is called the origin. Conventionally the axes are horizontal (x-axis) and vertical (y-axis) and distances from the origin are marked along these axes. The position of any point in the plane can be uniquely identified by an ordered pair, (p, q) where p is the distance of the point along the x-axis (the abscissa) and q is the distance of the point along the y-axis (the ordinate).

ab is a straight line in the plane p.

Point

Then it is in the plane!

A reflection in a line l is a correspondence that pairs each point in the plane and not on the linewith point P' such that l is the perpendicular bisector of segment PP'. IF P is on l then P is paired with itself ... Under a reflection the image is laterally inverted. Thus reflection does NOT preserve orientation...