Let the point P have coordinates (p, q, r) and let the equation of the plane be ax + by +cz + d = 0Then the distance from the point to the plane is
abs(ap + bq + cr) / sqrt(a^2 + b^2 + c^2).
To find the x-coordinate of a point on the xy-plane, you look at the horizontal distance of the point from the y-axis. The y-coordinate of a point on the xy-plane is the vertical distance of the point from the x-axis.
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True. The distance formula, which is derived from the Pythagorean theorem, calculates the distance between two points in a plane. When finding the distance between a point ((x, y)) and the origin ((0, 0)), the formula simplifies to (d = \sqrt{x^2 + y^2}), which directly corresponds to the Pythagorean theorem. Thus, in this specific case, the distance formula is indeed equivalent to the Pythagorean theorem.
graph it
To find the x-coordinate of a point on the xy-plane, you look at the horizontal distance of the point from the y-axis. The y-coordinate of a point on the xy-plane is the vertical distance of the point from the x-axis.
another point
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Unless the line is a subset of the plane, the intersection is a point.
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well, you find the two cooridinates on the plane and then graph them! KINDA EASY!
graph it
You use the distance formula.
The answer is the x coordinate of the point.
To find the horizontal distance of an object dropped by a plane, you can use the formula: distance = velocity x time. First, calculate the time it takes for the object to fall using the formula: time = √(2 x height / g), where g is the acceleration due to gravity (9.81 m/s^2). Then, multiply the time by the horizontal velocity of the plane to find the horizontal distance the object travels.