Let the point P have coordinates (p, q, r) and let the equation of the plane be ax + by +cz + d = 0Then the distance from the point to the plane is
abs(ap + bq + cr) / sqrt(a^2 + b^2 + c^2).
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To find the x-coordinate of a point on the xy-plane, you look at the horizontal distance of the point from the y-axis. The y-coordinate of a point on the xy-plane is the vertical distance of the point from the x-axis.
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The answer is the x coordinate of the point.