There can't be any such polygon. The regular polygon with the smallest interior
angles is the equilateral triangle. Each of those is 60°, and as you add more sides,
the interior angles get bigger ... 90° in a square, 108° in a pentagon etc.
If you start with the general rule that the sum of the interior angles of a polygon
with 'n' sides is (n - 2) times 180°, and work it backwards, then you'd get 27° for
each interior angle of a regular polygon with 2.353 sides. Nice job !
the sum of the interior angles in a 27 sided polygon is 4500.
It is 4500 degrees.
4500 degrees
The sum of the interior angles of a polygon with n sides is (n-2)*180 degrees. Here, n = 27, so the sum of the interior angles is (27-2)*180 = 25*180 = 4500 degrees.
The sum of the exterior angles of any polygon, including a 27 sided one, is 360 degrees.
Providing that it's a regular 27 sided polygon then the interior angles add up to 4500 degrees and each interior measures 166o40'0''
180 - (27 + 58)...
If the two base angles of an isosceles triangle are both 27 degrees then the vertex angle is 126 degrees because the sum of a triangles angles is always 180 degrees, 27 and 27 is 54, 180-54 is 126.
The sum of the interior angles of a polygon with n sides is (n-2)*180 degrees So (n-2)*180 = 4500 Hence n - 2 = 4500/180 = 25 and then n = 25 + 2 = 27.
4500 dgrees
Assuming the sum refers to that of the interior angles, the polygon has 27 sides.
Sum of interior angles = 180*(27-2) degrees = 4500 deg.