They are: 2*3 = 6
Do you mean prime factors? The prime factors of 1411 are 17 and 83.
Two distinct prime factors, six total prime factors.
Prime Factorization: 2,2,2,3,3,5,5,17 The factors are all multiple combinations of these numbers.
no
There are infinitely many numbers which have 6 prime factors.
Any multiple of 20 includes the prime factors of 20.
A prime multiple is when a number is expressed as the product of its prime factors as for example: 2*3*5*7 = 210
No, it is not possible. Every multiple of 21 is a composite number. 21 is a composite number and its factors are 1, 3, 7 and 21(4 factors). Any multiple of 21 must have all the factors of 21. So, every multiple of 21 has at least 4 factors. And a prime number has only two factors so, any multiple of 21 can't be prime.
A prime factor cannot be a multiple of anything (other than 1).
126 has only three prime factors. They are: 2, 3, 7.
Prime factors of 6 are 2 and 3
2 and 7