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The distributive property of multiplication over addition.

Q: What property involves multiplying a sum by a number?

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The distributive property of multiplication over addition.

It's a Crossword Clue Website if you look it up there's tons of them.

Yes. This is called the distributive property. For example: a(1 + 2 + 3 + ... + n) = 1a + 2a + 3a ... + na

== The sum of any number and zero is that number.(2+0== 2) == the sum of any number and zero is that number. (2+0=2)

"Proberty" is not a word. You're looking for "distributive property." The distributive property says that x(a + b) = xa + xb. (Multiplying the sum of two numbers by a third number is the same as summing the products of those two numbers multiplied individually by the third number.)

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The answer is the distributive property

Distributive property

The distributive property of multiplication over addition.

That's the distributive property.

It's a Crossword Clue Website if you look it up there's tons of them.

According to this property, multiplying the sum of two or more addends by a number will give the same result as multiplying each addend individually by the number and then adding the products together.

The distributive property states that multiplying a sum by a number gives the same result as multiplying each addend by the number and then adding the products together.

This is called the "distributive property" and has applications in algebra.

The distrubutive property.... Multiplying a sum by a number is the same as multiplying each addend by the number and then adding the products. EXAMPLE: 3x(2+4)=18 (3x2) + (3x4) = 18

What Is Distributive Property? According to this property, multiplying the sum of two or more addends by a number will give the same result as multiplying each addend individually by the number and then adding the products together.

Multiplying a sum by a number gives the same result as multiplying each addend by the number and then adding the products together.

Yes. This is called the distributive property. For example: a(1 + 2 + 3 + ... + n) = 1a + 2a + 3a ... + na