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What resistance do you need to reduce 13 Volts 1 Amp to 6 Volts 1 Amp?
Wiki User
∙ 11y ago
R = voltage drop divided by current
13-6 = 7 volts, 7/1 is 7 ohms. If you have a device that has inrush (e.g., a motor or coil) you could have short-lived spikes well over triple the current, making it likely the voltage will drop during startup, which could damage the device.
Personally, I would use a voltage divider to remove current from the equation:
R2 = R1/ (v.in/v.out - 1)
0.86 x R2 = R1 (e.g., R2 is 1000 ohms and R1 is 860 ohms)
Wiki User
∙ 11y ago
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1 amp current at 14 volts causes a .9 volt drop across a switch. what is the resistance at the switch?
V = I*RIf you solved this for resistance, this means you would have:V/I = RYou set V = .9 volts, I = 1 amp, and solve to get .9 Ohms.
What is the resistance of a 230v and 10 amp circuit?
You can't really convert that. If you multiply volts and amperes, you get watts, a unit of power. Watts is equivalent to joules/second. If you multiply volts x amperes x seconds, you get joules.
What is the current through a 4 and 8 ohm resister in sereis with 12 volts across both resisters?
Total resistance (thevinen resistance) = 4 + 8 Total voltage = 12 volts. Ohms law: I = V / R Therefore I = 12/12 = 1 amp.
If the potential difference across a load is 60 volts and the resistance of the load is 10 ohms the current is amperes.?
It's not that simple. The basic formula is Volts / Ohms = Amps. For 30 Volts you'd get 0.5 Amps, for 60 Volts you'd get 1 Amp, for 120 Volts you'd get 2 Amps.
Two 12 volt batteries in series one has 4 amp's another has 4 amp's they are connected across a 2 ohm load the current flowing in the circuit is?
Volts = Current x Resistance. You have 24 Volts divided by 2 ohms and the draw will be 12 amps. Your batteries will fail quickly if not spectacularly.
110v and the current is 10 a what is the resistance?
Resistance is Volts over Current 11 Ohm = 110Volt / 10 Amp
If the current through a heater coil is 5 amp and the supply voltage is 120 volts the coil resistance is?
The formula you are looking for is R = E/I. Resistance = Volts/Amps.
1 amp current at 14 volts causes a .9 volt drop across a switch. what is the resistance at the switch?
V = I*RIf you solved this for resistance, this means you would have:V/I = RYou set V = .9 volts, I = 1 amp, and solve to get .9 Ohms.
How do you measur ampere?
You use an "amp gauge" to measure amps in an actual circuit. It is hooked in series with the load. It can be placed anywhere in the circuit as long as it is hooked in series. Mathematically, you have to know the resistance, or wattage and voltage of a circuit. Volts=amps*resistance or amps=volts/resistance, or resistance=volts/amps. Ohms law!
What is the resistance of an object that uses 220 volts and draws 1 amp?
The formula you are looking for is R = E/I.
What is the resistance of a lamp operating at 115 volts and using 0.25 amperes of current?
The resistance of a lamp operating at 115 volts and using 0.25 amp of current is 460. The relationship I used is Ohm's law.
What is the resistance of a 230v and 10 amp circuit?
You can't really convert that. If you multiply volts and amperes, you get watts, a unit of power. Watts is equivalent to joules/second. If you multiply volts x amperes x seconds, you get joules.
How do you calculate amperage when given the values of watts and volts?
With an instrument called a multimeter. The single meter incorporates within it a volt meter, an ohm meter and an amp meter. For higher amperages a clamp on amp meter is recommended as the circuit does not have to be opened to take a reading.
How many volts do you need to power 2 watts?
watts = volts x amps, example-2 watts=2 volts x 1 amp, example- 2 watts=120 volts x .60 amp.
How many volts is 2 gauge 200 amp 3 ohms?
Ohm's Law states Volts = Amps x Resistance. You would need to apply 600 volts across 3 ohm load to have 200 Amps flow in circuit. Not sure what you are really asking and why you mentioned 2 gauge.
How many watts of electric on a 13 amp fuse 240 volts?
You need the formula: Amps * Volts = Watts But you get to do the math.
What will happen if you undo a bulb in a parallel circuit?
The bulb you remove will go out :) Overall current will also be reduced proportional to the resistance of the bulb being removed. Lets say you have two 60 W incandescent bulbs in parallel and they each are drawing 1/2 Amp (60W = 120 Volts x 1/2 Amp). The resistance of each bulb is 240 Ohms (120 Volts / .5 Amps). The parallel resistance is 120 Ohms so 1 Amp is being drawn. When one of the two bulbs is removed the resistance changes from 120 Ohms to 240 Ohms, reducing the current from 1 Amp to 1/2 Amp.
