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R = voltage drop divided by current

13-6 = 7 volts, 7/1 is 7 ohms. If you have a device that has inrush (e.g., a motor or coil) you could have short-lived spikes well over triple the current, making it likely the voltage will drop during startup, which could damage the device.

Personally, I would use a voltage divider to remove current from the equation:

R2 = R1/ (v.in/v.out - 1)

0.86 x R2 = R1 (e.g., R2 is 1000 ohms and R1 is 860 ohms)

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12y ago

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