R = voltage drop divided by current
13-6 = 7 volts, 7/1 is 7 ohms. If you have a device that has inrush (e.g., a motor or coil) you could have short-lived spikes well over triple the current, making it likely the voltage will drop during startup, which could damage the device.
Personally, I would use a voltage divider to remove current from the equation:
R2 = R1/ (v.in/v.out - 1)
0.86 x R2 = R1 (e.g., R2 is 1000 ohms and R1 is 860 ohms)
V = I*RIf you solved this for resistance, this means you would have:V/I = RYou set V = .9 volts, I = 1 amp, and solve to get .9 Ohms.
You can't really convert that. If you multiply volts and amperes, you get watts, a unit of power. Watts is equivalent to joules/second. If you multiply volts x amperes x seconds, you get joules.
It's not that simple. The basic formula is Volts / Ohms = Amps. For 30 Volts you'd get 0.5 Amps, for 60 Volts you'd get 1 Amp, for 120 Volts you'd get 2 Amps.
Total resistance (thevinen resistance) = 4 + 8 Total voltage = 12 volts. Ohms law: I = V / R Therefore I = 12/12 = 1 amp.
Volts = Current x Resistance. You have 24 Volts divided by 2 ohms and the draw will be 12 amps. Your batteries will fail quickly if not spectacularly.
Resistance is Volts over Current 11 Ohm = 110Volt / 10 Amp
The formula you are looking for is R = E/I. Resistance = Volts/Amps.
The relationship between volts and amps in an electrical circuit is defined by Ohm's Law, which states that voltage (V) is equal to the current (I) multiplied by the resistance (R) in the circuit. In other words, volts per amp is a measure of resistance in the circuit.
You would need a step-down transformer to reduce the voltage from 240 volts to 120 volts. Then, you would need to use a 15 amp-rated outlet or wiring to ensure the circuit is not overloaded. It is important to follow proper electrical codes and regulations when making such changes.
V = I*RIf you solved this for resistance, this means you would have:V/I = RYou set V = .9 volts, I = 1 amp, and solve to get .9 Ohms.
The formula you are looking for is R = E/I.
You use an "amp gauge" to measure amps in an actual circuit. It is hooked in series with the load. It can be placed anywhere in the circuit as long as it is hooked in series. Mathematically, you have to know the resistance, or wattage and voltage of a circuit. Volts=amps*resistance or amps=volts/resistance, or resistance=volts/amps. Ohms law!
The resistance of a lamp operating at 115 volts and using 0.25 amp of current is 460. The relationship I used is Ohm's law.
You can't really convert that. If you multiply volts and amperes, you get watts, a unit of power. Watts is equivalent to joules/second. If you multiply volts x amperes x seconds, you get joules.
watts = volts x amps, example-2 watts=2 volts x 1 amp, example- 2 watts=120 volts x .60 amp.
To calculate the amperage, you need to know the resistance in the circuit. Amperage is calculated using Ohm's Law: Amperage (A) = Voltage (V) / Resistance (R). Without knowing the resistance, we cannot determine the amperage.
With an instrument called a multimeter. The single meter incorporates within it a volt meter, an ohm meter and an amp meter. For higher amperages a clamp on amp meter is recommended as the circuit does not have to be opened to take a reading.