Best Answer

Could be anything! For example:

{sqrt(7)}

is one such set.

Probable "desired" answer is the set of Irrational Numbers

Q: What set contains the square root of 7?

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no, 28 has no whole square root; the square root of 49 is 7

irrational

7 times the square root of 7

JACK

Square root of 49 = 7... Square root of 9 = 3... 3 x 7 = 21

Related questions

No, the square root of 7 is NOT an Integer ...The square root of 7 = 2.64575131106

Seven.

2

Square root of 2 = 1.414213562... Square root of 7 = 2.645751311... The sum is 4.059964873...

no, 28 has no whole square root; the square root of 49 is 7

the 4th root of 49 is the square root of the square root of 49 since square root 49 =7 then simplify is square root of 7

The square root of 49 is 7.7 times 7 is 49, so the square root of 49 is 7. 7

yes. Examples: the square root of 7 times the square root of 7 = 7 the square root of 7 times one over the square root of 7 = 1

The square root of 49 is 7, because 7 x 7 = 49

irrational

Square root(7 billion) = 83,666.0027

7 times the square root of 7