7 ÷ 2 + (√3) = 5.232050808
(7*sqrt(2))/2 (Seven time the square root of 2, divided by two)
2
Square root of 15 plus square root of 7
98 is 49 times 2 so the square root of 98 is the square root of 49 times the square root of 2. But the square root of 49 is 7 , so the answer is 7 times the square root of 2.
24
if x^2 = 49, then the square root property says you can take the square root of both sides as long as you make one a plus-minus. x^2 = 49, which means square root of x^2 = plus minus the square root of 49 the square root of 49 is 7, so +- 7. We get: x = plus/minus 7 (this means either positive 7 or negative 7)
7 ÷ 2 + (√3) = 5.232050808
(7*sqrt(2))/2 (Seven time the square root of 2, divided by two)
2
The square root cannot be simplified.
(sqrt(9) - sqrt(12) + sqrt(16)) x sqrt(2) = -2 sqrt(6) + 7 sqrt(2)
10 square root of 3.
Square root of 15 plus square root of 7
x + y = -7xy = -15y = -x - 7x(-x - 7) = -15-x^2 - 7x = -15 multiplying both sides by -1x^2 + 7x = 15 complete the square;(x^2 + 7x + 49/4) = 15 + 49/4(x + 7/2)^2 = 109/4(x + 7/2) = (plus & minus)square root of 109/41. x = -7/2 + (square root of 109)/22. x = -7/2 - (square root of 109)/2y = -x - 7y = -[-7/2 + (square root of 109)/2] - 7 = 7/2 - (square root of 109)/2 - 71. y = -7/2 - (square root of 109)/2 ory = -x - 7y = -[-7/2 - (square root of 109)/2] - 7 = 7/2 + (square root of 109)/2 - 72. y = -7/2 + (square root of 109)/2 Check it:
It is irrational
It is: 4+7 = 11