Volume = 1/3*25*25*60 = 12500*pi cubic cm
Diameter = circumference / PI = 50cm/3.1415 = 15.92cm
Subtract 50cm from external diameter.
V = Length x Width x Height 50x35=1750 122500/1750=70 The height of the rectangular prism is 70cm.
The long diagonal will be sqrt(7500) cm = 86.60 cm (to 2 dp)
Fill a market beaker to a specific measured volume. (Eg. 50cm cubed, make sure you have not filled the beaker with water). Now place the object in the beaker with water. The water level should rise (Eg. from 50cm cubed to 60cm cubed). The difference in the original volume and the final volume is the volume of the object. That is the water displacement method.
Diameter = circumference / PI = 50cm/3.1415 = 15.92cm
A liter equals 1dm³ in volume. Since 50dm³ are 50000cm³, a cuboid with the dimensions 50cm * 50cm* 20cm would fit as well as a tube of 1m height and 25.23cm diameter.
Volume = pi*d*h = 1.5708 metres3 or 1570.8 litres
Radius = Diameter / 2 = 25 cm.
Subtract 50cm from external diameter.
39cm-50cm
"... if it is 50cm". The question does not say what "it" is. A side length, a diagonal, something else.
Divide by 2.54 and you will have the length in inches.
V = Length x Width x Height 50x35=1750 122500/1750=70 The height of the rectangular prism is 70cm.
The long diagonal will be sqrt(7500) cm = 86.60 cm (to 2 dp)
Diameter of circle: 50/pi = 16 cm rounded to the nearest whole number
The volume of this cone is 37,699 cm3