The circumference of a circle is calculated (when one knows the diameter) by multiplying the diameter by pi = we'll use 3.1416 as pi here.
So we are told that 5 rotations = 2 metres, so the circumference = (2 ÷ 5) metre.
Let's convert that to millimetres and we get (2000 ÷ 5) or 400
So, if the circumference = 400 then the diameter = (400 ÷ 3.1416) or 127.3 millimetres
So, the wheel has a height of 127.3 millimetres
A wheel whch goes 6 metres in 10 rotations has a circumference of 0.6 metres, or 600 millimetres. the diameter of a circle is the circumference divided by pi, or in this case 600 / 3.1416... whcih equals 190.985 so almost exactly 191 millimetres. The wheel has a height of 191 millimetres
The size of the wheel effects the number of rotations of the tire but not the speed at which the rotations occur. A huge wheel moving at ten miles per hour is going no faster than a small wheel going at ten miles per hour. The difference is that the larger tire makes fewer rotations than the smaller one, but the speed of the rotations does not change.
A bicycle should not make any rotations! The number of rotations made by the wheels of a bicycle will depend on the wheel size.
No, a trundle wheel works because the wheel has a circumference of exactly 1 meter. This means that every time the wheel has turned around exactly once, you've traveled 1 meter. So, although the wheel is round, they have exactly the same size.
None of these transformations affect the size nor shape of the image.
A typical beach ball is about a quarter of a meter in radius. They are not all exactly the same size, so this answer is not precise.
The wheel size does affect its speed.
Impossible to say, as it depends on the size of the wheel. To find out, calculate the circumference of the Wheels.
As the size of the wheel increases the necessary force needed to pull the wheel decreases
The original wheel size is 15"
Explain how the mechanical advantage of a wheel and axle change as the size of the wheel increases?
This is a simple algebra problem. The Sun has a diameter of 1,390,000 km, and the Earth has a diameter of 12,756 km. If I'm making a model of the Sun that is 1.26 meters in diameter, what should the diameter of the model Earth be? So, 12756/1390000*1.226 = 0.0112509755 meters, or 1.125 cm. So, if the sun-model is 1.26 meters, about the size of a bicycle wheel, then the earth-model is about the size of a pea.