Depends on length. The more length, the more resistance.
Wire size is governed by amperage not voltage. Voltage is an insulation factor when talking about wire. Add up the amperage of fixtures you want in the circuit. Once that is found then the size of the wire can be calculated.
A 1/0 aluminum conductor will limit the voltage drop to 3% or less when supplying 30 amps for 500 feet on a 240 volt system.
As with any electrical installation, the wire size used depends on the expected maximum current the wire will carry. That cannot be determined by voltage alone.
The wire size depends on how much current it will conduct.
Depends on the size of the circuit which you did not list.
6 AWG
In the US and Canada, 10 Guage wire will suffice
Wire size is governed by amperage not voltage. Voltage is an insulation factor when talking about wire. Add up the amperage of fixtures you want in the circuit. Once that is found then the size of the wire can be calculated.
A 1/0 aluminum conductor will limit the voltage drop to 3% or less when supplying 30 amps for 500 feet on a 240 volt system.
It depends on the supply voltage because at that distance the size of the wire is calculated on the volt-drop which is 5% of the supply voltage, or 3% in some countries. The allowable resistance equals the volt-drop divided by the current, then you can use wire tables to find the wire size, remembering that a supply needs 2 wires which are in series so that their resistances add. <<>> To answer this question a voltage value has to be stated. This is due to the higher the voltage the lower the current on a specific load. The lower the current, the smaller the wire size can be.
Use 8 gauge wire.
Yes, no problem at all going to a larger ampacity of wire. Larger size wire yes, smaller size wire no.
8 gauge will be sufficient with less than a half volt drop
A #10 copper conductor will limit the voltage drop to 3% or less when supplying 21 amps for 150 feet on a 240 volt system.
# 3 gauge
4 copper
As with any electrical installation, the wire size used depends on the expected maximum current the wire will carry. That cannot be determined by voltage alone.