To answer this question a voltage must be given.
Watts = Volts x Amps, if you use your algebra you will find that it's approx 14 Amps.
Copper is a better conductor by weight, but aluminum is better by weight, so the copper will be thinner but heavier. You will see that a 250 kcmil aluminium wire will get you 170 amps at 60 degC while a 000 (or 3/0) copper wire will get you 165 amps at 60 degC. I think you mean circular mils, not square millimeters.
Copper is a better conductor by weight, but aluminum is better by weight, so the copper will be thinner but heavier. You will see that a 250 kcmil aluminium wire will get you 170 amps at 60 degC while a 000 (or 3/0) copper wire will get you 165 amps at 60 degC. I think you mean circular mils, not square millimeters.
Depends how the weight is distributed. i weight 170 and wear a size 8 (eight)
10
A 200 mA fuse would be appropriate to protect a DC relay with a 170 mA rating. Choose the next higher standard fuse rating to ensure the relay is adequately protected while allowing for any slight variations in current draw.
A ton of A/C is 844.2 watts, so 5 tons is 4222.5 watts. Design extra 10 percent for constant load for total of 4650 W. Using 240 volts at 20 amps (W = Amps x volts), on 12 AWG wire, you would get 155 feet before having a 5% voltage drop. If inrush current is 30 amps at startup, you would have 7.5 percent drop in the cable during startup. To be safe, perhaps bump up a size (10 AWG) and have 4.7 percent drop during inrush (at 155 ft), or be able to run up to 170 feet at 30A load with 5 percent drop. In any case, because normal operating current is 20 A, you should use a 30 A breaker and thus 10 AWG wire, to be on safe side. If the unit is 120 V, the distances are halved for the same amount of drop.
Overall 200. 170 needed for roving
The temperature has no effect on the wire needed, only on the insulation and installation details. !70 A would require 35mm2 copper in free air. Soil disipates heat better than air, so the cable would take more current and be safe if it was in/on the ground. In any form of conduit, you'd need a bigger cable.
180-170 = 10 degrees and the polygon will have 36 sides
170, 70, 13
170