A triangular prism seems to fit the given description
a cube, or hexahedron.
that is a cube
I believe that such an object cannot exist in normal 3-d space. If there are 6 vertices, the maximum number of edges is 12.
I AM A SPACE FIGURE WITH 5 FACES, 8 EDGES, AND 4 CORNERS. which SPACE FIGURE AM i?
A cylinder.
A (genus-0) polyhedron must satisfy Euler's formula: V + F - E = 2. Setting V, E, F equal to the same value, say, X, we get X + X - X = 2 X = 2. A solid with two edges, vertices and faces is called a "digonal hosohedron", but it is not usually considered a three-dimensional figure, in euclidean space.
Assuming that a space figure means a 3-dimensional object, the answer is a square based pyramid.
4 vertices in 2 dimensional space has only one face with 4 edges. 4 vertices in 3 dimensional space has four faces with 4 edges. I don't know how to imagine dimensional spaces greater than 3, except with time as the 4th dimension. But even with that I cannot imagine a time vertex.
It is a very irregular enneahedron or nonahedron - a shape with 9 faces.
pyramid
It has 5 faces, 6 edges, 4 vertices, and 2 base. Bases are counted as faces too, but are polygonal and are translations of each other in space. So, they are congruent and are in parallel planes. * * * * * The above answer is utter nonsense. A triangular prism has 5 faces (two triangles and 3 rectangles), 9 edges and 6 vertices. Bases are counted as faces.
rectangular pyramid