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Answered 2013-07-23 21:16:38
It is not possible to answer the question as it appears because it makes no sense whatsoever.
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Is it never always or sometimes the sum of two positive integers is zero?
The sum of two positive integers is never zero. The sum of two numbers a and b can only be zero if a=-b, or a=0 and b=0. Since 0 is not a positive integer, and a and b cannot both be positive integers if a=-b, then it is impossible for the sum of two positive integers to be zero. _______________________________________________________________ The above answer is correct. Here is another way to say it: An integer is any whole number including negative numbers, positive numbers and zero. However, a "positive integer" is a whole number greater than zero. The "sum of two positive integers" means you are adding two numbers greater than zero together. Therefore, the sum of two positive integers can never be a negative integer, and can never be zero. Example: 1 + 1 = 2
Programme for sum of two integers using C?
int a = 1; int b = 2; int c = a + b; // Sum
What procedures will find the sum a plus b of two numbers where a and b represent any integers?
addition a + b
Flowchart to read 10 positive integers?
The flowchart to read 10 positive integers K>10 Start A N K=1 Sum = 0 Sum = Sum + K2 B Is Y Print K > 100? sum K=k+1 End B A
If two integers have the same sign what is the sine of their sum?
Sine(A+ B) = Sine(A)*Cosine(B) + Cosine(A)*Sine(B).
Is 'B' the correct answer?
On a multiple choice test with answers of A, B, C, and D, the answer of 'B' would only be the correct answer if all other choices are incorrect.
The variables a and b represent positive integers neither of which are divisible by 10 yet the product of a and b is 100000 Find the sum of a and b?
641
What two mixed numbers have a sum 3?
There are infinitely many answers: 1+a/b and 2-a/b for any pair of positive integers a and b, with a<b.
Associative principle for addition of integers?
The associative property states that, for the sum of three or more integers the order in which the summation in carried out does not make a difference to the answer. Thus, for any three integers, A, B and C: (A + B) + C = A + (B + C) and so, without ambiguity, we can write either as A + B + C. Note that A + B need not be the same as B + A. The order of the integers DOES matter. It is the order of the summing that does not.
What is the sun of four integers whose average is 15?
I assume you meant "sum". The answer is 60. 60=4 (integers) * 15 (average value of the integers). average of 4 integers = 15 --> (a + b + c + d)/4 = 15 --> (a + b + c + d) = 15 * 4 --> (a + b + c + d) = 60
If a and b integers and a b then a b?
If a and b are integers, then a times b is an integer.
Write a program to find the number of and sum of all integers greater than 100 and less than 200 that are divisible by 2?
cls rem a program to sum two number read a,b data 10,30 sum=a+b print "the result of sum=";sum end
What is 2 integers that have a sum of 2 and a difference of 8?
Given:a + b = 2a - b = 8Then:a = b + 8∴ (b + 8) + b = 2∴ 2b = -6∴ b = -3∴ a = 5
What is the plural spelling for formula?
A. formulaii B. The above is incorrect. "Formulae" and "formulas" are correct.
Write a program in c for arithmetic operation between two integers?
#include<stdio.h> #include<conio.> void main() { int a,b,sum; clrscr(); cin<<"enter value of a"; cout>>a; cin<<"enter value of b"; cout<<b; sum=a+b; cout<<"sum of two numbers=" getch(); }
Prove that if a and b are rational numbers then a plus b is a rational number?
Because a is rational, there exist integers m and n such that a=m/n. Because b is rational, there exist integers p and q such that b=p/q. Consider a+b. a+b=(m/n)+(p/q)=(mq/nq)+(pn/mq)=(mq+pn)/(nq). (mq+pn) is an integer because the product of two integers is an integer, and the sum of two integers is an integer. nq is an integer since the product of two integers is an integer. Because a+b equals the quotient of two integers, a+b is rational.
When is the sum of two integers greater than the difference?
Call the numbers "a" and "b": a + b > a - b b > -b 2b > 0 b > 0 In other words, when the second number is greater than zero.
What are the 4 consecutive odd integers where the sum of the middle two integers is equal to 24?
9, 11, 13, 15 The solution equation is A + B = 24 where B = A +2 (the consecutive odd integer) 2A +2 = 24 A = 11, B = 13
When a nucleus splits the mass is equal to the?
accourding to novanet the correct answer (the sum of A and B).
If a and b are positive integers neither of which is divisible be 10 and if ab equals 10000 what is the sum of a plus b?
625*16=10000625+16=641
Why is the sum of a fraction and a whole number not a whole number?
Look at it the other way - by reverting the operation. The reason it is not a whole number is because if it where, then the subtraction of two integers would be a fraction! If a + b = c (a is a non-integer fraction, b and c are integers), then c - b = a. You would have a fraction as a result of subtracting two integers. However, adding or subtracting two integers always gives you an integer.
Is 'A' the correct answer?
On a multiple choice test with answers of A, B, C, and D, the answer of 'A' would only be the correct answer if all other choices are incorrect.
What procedures will find the sum a - b of two numbers where a and b represent any integer?
If b is positive, then reduce each of a and b by subtracting 1, repeatedly until b is zero. If b is negative, repeatedly add 1 to both until b is zero. The final value of a is the result you ask for. If a and b are two integers, their sum is a+b, not a-b.
Factor x squared -8x plus 3?
x^2-8x+3 This expression cannot be factored as (x+a)(x+b) where a and b are integers. This is because you cannot find two integers such that their sum is -8 and product 3.
If 2 integers have a difference of -18 and a sum of 2 what are the 2 integers?
Let a and b be the two numbersThe data we have is:a - b = -18 ........ equation (1)a + b = 2 ........ equation (2)Adding equations (1) and (2)(a - b) + (a + b) = -18 + 22a = -16a = -8Using a = -8 in equation (2),-8 + b = 2b = 2 + 8b = 10
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