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actually 2n-3 is not an equation so there's no answer but if you will make into an equation it becomes 2n-3=o finding the value of n,2n-3=0,2n=3,n=3/2
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What does (2n)3 equal in properties of exponents.?
2n x 2n x 2n = 8n^3
How do you solve 5 subtract 2n equals 3?
5-2n=3 -2n=3-5 -2n=-2 n=1
What is the product of two consecutive odd integers is 23 more than their sum.?
It is a statement that is equivalent to the equation:(2n+1)*(2n+3) = (2n+1)+(2n+3) + 23.
How do you show work 2n -3 equals 5?
2n - 3 = 5Add 3 to each side:2n = 8Divide each side by 2:n = 4
In a algebra how do you solve for n in 2 times n divided by 3 equals 4?
2n/3 = 4 2n = 3*4 2n = 12 n = 6 :)
What does (2n)3 equal in properties of exponents.?
2n x 2n x 2n = 8n^3
How do you solve 5 subtract 2n equals 3?
5-2n=3 -2n=3-5 -2n=-2 n=1
How do you solve 2n plus 3?
Solve for n. 2n+3=0 2n=-3 n=-3/2
2n plus 35?
2n + 3 = 352n = 35 -32n = 32n = 32/2n = 16
What is the nth term of 5,7,9,11,13?
3=2n
What are 4 positive odd numbers whose sum of their squares equals 164?
Answer is 3, 5, 7, 9detailsassume the numbers are2n-3, 2n-1, 2n+1, 2n+3 ......................... (1)(2n-3) 2 + (2n-1) 2 + (2n+1) 2 + (2n+3) 2 = 16416n 2 + 20 = 16416n 2 = 144n2 = 9n = 3Substitute in eq 1 we get the answer above
What is the value of the experisson -2n 7 when n 3?
-2n +7 when n=3?
What is the product of two consecutive odd integers is 23 more than their sum.?
It is a statement that is equivalent to the equation:(2n+1)*(2n+3) = (2n+1)+(2n+3) + 23.
What is the number of elements in a set with 3 subsets?
No. of subsets = 2n - 1 3 = 2n - 1 3 + 1 = 2n - 1 + 1 4 = 2n 4/2 = 2n/2 2/1 = 1n/1 2 = n n = 2elements
How do you show work 2n -3 equals 5?
2n - 3 = 5Add 3 to each side:2n = 8Divide each side by 2:n = 4
What is 6n-3 equals 2n plus 9?
6n -3=2n+9 6n-2n=9+3 4n=12 n=12/4 n=3
What is the greatest whole number that MUST be a factor of the sum of any six consecutive positive odd numbers?
Let the first odd number be 2n-5 (n ≥ 3), then the 6 consecutive odd numbers are: 2n-5, 2n-3, 2n-1, 2n+1, 2n+3, 2n+5 And their sum is: 2n-5 + 2n-3 + 2n-1 + 2n+1 + 2n+3 + 2n+5 = 12n The greatest common factor for all n(≥ 3) of 12n is 12. Thus 12 is the greatest whole number that MUST be a factor of the sum of any six consecutive positive odd numbers.
