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Answer is 3, 5, 7, 9

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assume the numbers are
2n-3, 2n-1, 2n+1, 2n+3 ......................... (1)

(2n-3) 2 + (2n-1) 2 + (2n+1) 2 + (2n+3) 2 = 164

16n 2 + 20 = 164

16n 2 = 144

n2 = 9

n = 3

Substitute in eq 1 we get the answer above

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