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-- You haven't said what the object's speed was at the beginning of the

25 minutes. We'll assume that it started from rest at the beginning of

this whole exercise.

-- We're also going to work exclusively with the object's speed. Since you

haven't said anything about the direction in which it moves at any moment,

we have no way to work with velocity. Fortunately, it doesn't matter.

The motion occurs in three distinct periods, which we'll consider separately:

Period I:

Zero to 90 m/s in 25 minutes.

Average speed = 45 m/s.

Distance = (average speed) x (time) = (45 meter/sec) x (60 sec/min) x (25 min) = 67,500 meters.

Period II:

(90 meters/sec) x (3,600 sec/hour) x (2 hours) = 648,000 meters

Period III:

A perfect time-reversal of Period-I ... like running the video backwards.

Same distance as Period-I = 67,500 meters.

Total distance = (67,500) + (648,000) + (67,500) = 783 kilometers.

======================================================

Period-I

S = vit + 1/2 a t2

vi = 0

Acceleration = [ (90 meter/sec) x (1/25 min) ] x (1 min/60 sec) = 0.06 meter/sec2

t = 25 minutes = 1,500 sec

1/2 a t2 = 1/2 (0.06) (1,500)2 = 67,500 m

Period-II

S = v t = (90 meters/sec) x (2 hours) x (3,600 sec/hour) = 648,000 m

Period-III

Either recognize that Period-III is exactly the same as Period-I in reverse,

or else

you can use

S = vit + 1/2 a t2

vi = 90 meters/sec

t = 25 min = 1,500 sec

Acceleration = -0.06 meter/sec2

vit + 1/2 a t2 = (90)(1,500) + 1/2(-0.06)(1,500)2 = (135,000) + (-67,500) = 67,500 m

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Q: What the total distance if a body acquires velocity of 90 meter per second in 25 minutes and move with the same velocity for 2 hours and apply brakes then the body come to rest in 25 minutes?
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