The numbers are -6, -5 and -4.
The sum of the squares of the three consecutive integers 11, 13, 15 = 515
Divide the sum of the three consecutive odd integers by 3: 45/3 = 15. The smallest of these integers will be two less than 15 and the largest will be two more than 15, so the three consecutive odd integers will be 13, 15, and 17.
The integers are 11, 13 and 15.
a+(a+d)+(a+2d)=-15
They are -6, -5 and -4.
-14,-15,-16.
13+14+15 = 42
11, 13, 15
4, 5, and 6 are.
They are -15, -14 and -13.
13 + 15 + 17 = 45.
They are: -15-17-19 = -51