There is no 4-digit number that is divisible by 2356 and 10.
If the last digit is a zero, the number is divisible by 10.
Any whole number between 10 and 99, with a zero tacked on to the end of it, is.
If you multiply 2*9, you get 18. Multiply that by 10 to get a three digit number, and you get 180.
There is no such number. The smallest number divisible by 2356 and 10 is 11780.
There are many answers to it. 100,110,120,130,140,150,160,170,180,190,200,210,220,230,240,250,260,270, 280,290
Anything from 180 to 990 counting by 90.
There is no limit to the number of digits.If, for example, a X is a k-digit number which is divisible by 4 then 10*X is divisible by 4 and 10*X will be a (k+1)-digit number.
135. Every increase of 30 is also. Such as 165, 195, 225.
That would be 660.
An even number, by definition is divisible by 2. For the number to be divisible by 10, the last digit must be 0, which ensures it is an even number. Any number, with zero as the last digit will satisfy the requirements. So 111110 will do.
How about: 300
No. In order for a number to be divisible by 10, the ones digit must be zero (0).
No. A whole number is (evenly) divisible by 10 only if its last digit is ' 0 '.
A whole number is evenly divisible by 10 only if its last digit is a zero.
90 is divisible by 10 because it has a 0 as its end digit. Any number with a zero as the end digit gives an integer result when dividing by 10.