There are an infinite number of them.
Here are a few:
59, 61, and 60 are.
61 and 62.
The two numbers are 52 + 62 = 25 + 36 = 61
Two ways to solve:183/3= 61. So 61 is in the middle, and your other two numbers would be 60, and 62.The other way is algebraically. x+(x+1)+(x+2)=183 x is your starting number, and consecutive numbers would just be x+1, and x+2. Solve, to get the first number of 60, then just get 61 and 62.Final answer: 60, 61, 62.
60 and 1 if you add them. 61 and 1 if you multiply them. 62 and 1 if you subtract them. 61 and 1 if you divide them.
59, 61, and 60 are.
Prime numbers between 55 and 65 are 59 and 61.
The numbers are 59, 60 and 61. Also, 58, 60 and 62.
An infinite number, there is no limit, there is an infinite number of numbers between .61 and .62, there is an infinite number between .61 and .611 .61 .6101 .61001 etc.
62 64 66 68 70 72
They are 59 and 61
61 and 62.
61 & 62
The two numbers are 52 + 62 = 25 + 36 = 61
Two ways to solve:183/3= 61. So 61 is in the middle, and your other two numbers would be 60, and 62.The other way is algebraically. x+(x+1)+(x+2)=183 x is your starting number, and consecutive numbers would just be x+1, and x+2. Solve, to get the first number of 60, then just get 61 and 62.Final answer: 60, 61, 62.
60 and 1 if you add them. 61 and 1 if you multiply them. 62 and 1 if you subtract them. 61 and 1 if you divide them.
62 & 61