24
24
81
88 does.
64 Factors: 1, 2, 4, 8, 16, 32, and 64.
240
88
91 since the ones digit is 8 less than 9 and the two digits, 9+1 = 10, a two-digit number.
19?
One way to do this is multiply 8x3=24 so 24 has both as factors. Now multiply it by 10 and you have 240. That is a 3 digit number and sill has 8 and3 as factors.
There is no such two digit number. If the first digit is x and the second is y, then the number is 10x + y, its digit reverse is 10y + x, and: 10x + y + 8 = 10y + x → 9x + 8 = 9y → 9x + 8 = 18x → 9x = 8 → x = 9/8 BUT x must be a whole number.as x is a digit 1-9. ergo the problem as stated has no solution.
67 and 8 are factors of 536
The largest two-digit even number is 98. In the decimal system, each digit can range from 0 to 9, but for a two-digit number, the first digit cannot be zero. Since we are looking for an even number, the last digit must be an even number, which leaves us with 0, 2, 4, 6, or 8. Among these options, 8 is the largest even digit, resulting in 98 as the largest two-digit even number.