The sum of two fractions will be equal to one when the numerator and the denominator of their sum are the same. Example: 1/3 + 2/3 = 3/3 or 1
That their sum is always equal to the denominator.
To determine whether the sum of two fractions with a common denominator is greater than, less than, or equal to 1, you need to add the numerators of the fractions together and compare the result to the common denominator. If the sum of the numerators is greater than the denominator, the sum of the fractions will be greater than 1. If the sum of the numerators is less than the denominator, the sum of the fractions will be less than 1. If the sum of the numerators is equal to the denominator, the sum of the fractions will be equal to 1.
You can represent the two fractions with one fraction with a numerator equal to the sum of the two individual numerators (with sign) and a denominator equal to just one of the two denominators.
1/2 + 1/2 = 1
the sum the sum
You have to find the common denominator for the fractions, so multiply the "half" (2) by the "thirds" (3). These two numbers multiplied with give 6 as a common denominator. Then multiply the 1 by the 3, which will give 3/6ths, and the 2 by the other 2, which will give 4/6ths. Hmmm! it seems that 4/6ths is greater than 3/6ths, so you have to add a whole to the 3/6ths to make a big enough fraction to subtract. Doing that will give you 9/6ths and you can subtract the 4/6ths. So the answer would be 5/6ths. Try it.
the difference between two equal fractions is zero.
No. Each mixed number is made of a whole number and a fraction. When you add them, you have the sum of two whole numbers and two fractions. Since each whole number must be at least ' 1 ', the sum of two whole numbers must be at least ' 2 ', and the two fractions will always make it more than ' 2 '.
They will sum to the denominator.
If you convert both numbers into 6ths it is easier to work out. 1 and 1/2 is 9/6ths and 2/3rds is 4/6ths. so, 9/6ths - 4/6ths = 5/6ths.
If two fractions are equal then the difference between them is zero (0).