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Q: What two integers have a sum of ten and a product of seventyfive?

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The sum of the first ten positive integers is: 55

+5 and -15 do.

negative 15 and positive 5

The sum of the first ten positive integers, i.e. 1,2,3,4,5,6,7,8,9, and 10, is 55. The sum of the first ten negative integers, i.e. -1,-2,-3,-4,-5,-6,-7,-8,-9, and -10 is -55. The sum of the first ten positive integers plus the sum of the first ten negative integers is 0.

the product of 8 and the sum of 10 and -7

sum = 10 1/2 product = 5 difference = 51/2

The integers are -4, -3, -2, -1, 0, 1, 2, 3, 4 and 5. The largest is five.

48

The product is the result of a multiplication sum. Since this sum has just one number in the question part, it is impossible to find the product of this single number.

5+5 = 10 (Sum is ten)5*5 = 25 (Product is 25)*this product is maximum for all any 2 real numbers that == 10

10+(X)+(X+1)=196 10+2X+1=196 11+2X=196 2X=185 X=92.5 Therefore, ten plus the sum of two consecutive integers can not be even.

5,000,000*2=10,000,000 5,000,000 and 2

public class sum { public static void main(String args[]){ int sum=0; for(int i=1;i<=10;i++){ sum=sum+i; } System.out.println(sum); } }

Ten and minus twelve or twelve and minus ten.

3.5858 and 6.4142 approx.

public class Sum { public static void main(String[] args) { int sum=0; for(int i=1; i<=10; i++) sum+=i; System.out.println(sum); } }

10-11-12

you can use the condition statement like for(i=0:i<=10;i++)

5 and -15.

The number of 0s in the product is equal to the sum of the number of 0s in the whole number that you started with and the power [of ten].

its 5 squared divided by the sum of 28 to the power of ten. -maths teacher

20

Add the numbers into one variable as you read them in. But if you prefer, you can read the numbers into an array and then use a loop to add the numbers together.

1, 2 and 3.

ten