The sum of the first 10 positive integers 1,2,3,4,5,6,7,8,9 and 10 is 55. The sum of the first 10 negative integers -1,-2,-3,-4,-5,-6,-7,-8,-9 and -10 is -55. The sum of the first 10 positive plus the sum of the first 10 negative integers is 0
Many people would consider 0 to be the first even positive integer, however similar to the neutron in an atom, 0 holds a neutral position. Meaning it is neither a proton (+1) or electron (-1). So our first positive even integer would be 2.2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18 + 20 = 110, which is the sum of the first ten evenly positive integers.
2520
Ten of them.
Sum = 0 For N = 1 to 10 Sum = Sum + 2*N Next N Print Sum
The sum of the first 10 positive integers 1,2,3,4,5,6,7,8,9 and 10 is 55. The sum of the first 10 negative integers -1,-2,-3,-4,-5,-6,-7,-8,-9 and -10 is -55. The sum of the first 10 positive plus the sum of the first 10 negative integers is 0
negative 15 and positive 5
The first ten positive numbers total 55.
Many people would consider 0 to be the first even positive integer, however similar to the neutron in an atom, 0 holds a neutral position. Meaning it is neither a proton (+1) or electron (-1). So our first positive even integer would be 2.2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18 + 20 = 110, which is the sum of the first ten evenly positive integers.
2520
There are no such integers. In fact, there are no real numbers that satisfy the requirements.
The sum of the first 100 odd numbers (1 through 199) is 10000 (ten thou)
public class sum { public static void main(String args[]){ int sum=0; for(int i=1;i<=10;i++){ sum=sum+i; } System.out.println(sum); } }
Ten of them.
10-11-12
The first ten consecutive composite positive integers are: 114 115 116 117 118 119 120 121 122 123
No, there are an infinite number of integers. So, there would be an infinite (infinity/2-1) number of positive integers. And, there would be an infinite (infinity-10) number of integers greater than ten.