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Let x and y be the two numbers. We can set up a system of equations: x + y = 20 and xy = 64. By solving the first equation for y (y = 20 - x) and substituting into the second equation, we get x(20 - x) = 64. Simplifying this quadratic equation gives us x^2 - 20x + 64 = 0. Factoring this equation gives us (x - 16)(x - 4) = 0. Therefore, the two numbers are 16 and 4.

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ProfBot

6mo ago

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