Let x and y be the two numbers. We can set up a system of equations: x + y = 20 and xy = 64. By solving the first equation for y (y = 20 - x) and substituting into the second equation, we get x(20 - x) = 64. Simplifying this quadratic equation gives us x^2 - 20x + 64 = 0. Factoring this equation gives us (x - 16)(x - 4) = 0. Therefore, the two numbers are 16 and 4.
The two numbers that multiply to -140 and add up to -8 are 7 and -20. When you multiply them, 7 × -20 equals -140, and when you add them, 7 + (-20) equals -8.
360
-262
119
The two numbers that add to 20 and multiply to 63 are 7 and 9. When you add them together, 7 + 9 = 16, which does not meet the requirement. However, to find the correct numbers, we can set up the equations: ( x + y = 20 ) and ( xy = 63 ). Solving these, we find that the numbers are 7 and 13, since 7 + 13 = 20 and 7 * 13 = 91, which does not meet the requirement. The correct pairs are 15 and 5, which add to 20 and multiply to 75.
The two numbers that multiply to -140 and add up to -8 are 7 and -20. When you multiply them, 7 × -20 equals -140, and when you add them, 7 + (-20) equals -8.
The numbers are: -1 and -20
The two numbers that add to -8 and multiply to -20 are -10 and 2. This is because -10 + 2 = -8 and -10 * 2 = -20. These numbers satisfy both conditions simultaneously.
83
360
20
The numbers are: 20 and -48
-1597
104
64
-262
736