0
a+b=6, or a=6-b
a*b=1
substitute for a in the 2nd equation, using the first equation:
(6-b)*b=1
-b2+6b-1=0
b2-6b+1=0
Using the quadratic equation,
b = (6 +- (36-4).5)/2 = 3 +- 2(2).5
a = 6 - (3 +- 2(2).5) = 3 +- 2(2).5
(a,b) = (3+2(2).5,3-2(2).5) or (3-2(2).5,3+2(2).5)
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∙ 13y ago
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